Project Euler #13: Large sum | Hackerrank | Project Euler

  Large sum

Work out the first ten digits of the sum of N 50 - digit numbers.

Input Format

First line contains N, next N lines contain a 50 digit number each.

Constraints

1<=N<=10^3

Output Format

Print only first 10 digit of the final sum

Sample Input

5

37107287533902102798797998220837590246510135740250

46376937677490009712648124896970078050417018260538

74324986199524741059474233309513058123726617309629

91942213363574161572522430563301811072406154908250

23067588207539346171171980310421047513778063246676

Sample Output

2728190129

Explanation

Summing the numbers we get 2728190129820036131461476701043585006837989465343, first 10 digits are 2728190129.

Solution in python:

n = int(input())

tot=0

for i in range(n):

    a=int(input())

    tot=int(tot)+a;

while (tot >= 10000000000):

    tot = tot // 10

print(tot)

You can also run it on an online IDE :

https://ide.geeksforgeeks.org/40288644-2c69-4867-89bc-2432afbb48a5

Your feedback are always welcome! If you have any doubt you 

can contact me or leave a comment!  

Happy Coding!! Cheers!!!